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:Therefore, some C is not A.
:Therefore, some C is not A.


This is valid only if A is a [[proper subset]] of B and/or B is a proper subset of C. However, this argument reaches a faulty conclusion if A, B, and C are [[equivalence relation|equivalent]].<ref>{{cite book |title=The use of words in reasoning |author=Alfred Sidgwick |year=1901 |publisher=A. & C. Black |url=https://archive.org/details/useofwordsinreas00sidgiala |pages=[https://archive.org/details/useofwordsinreas00sidgiala/page/297 297]–300}}</ref><ref>{{cite document |page=16 |title=Equivalence of syllogisms |author=Fred Richman |date=July 26, 2003 |publisher=Florida Atlantic University |url=http://www.math.fau.edu/richman/docs/syllog-4.pdf |url-status=dead |archive-url=https://web.archive.org/web/20100619151753/http://math.fau.edu/Richman/Docs/syllog-4.pdf |archive-date=June 19, 2010 }}</ref> In the case that A&nbsp;=&nbsp;B&nbsp;=&nbsp;C, the conclusion of the following simple aaa-1 syllogism would contradict the aao-4 argument above:
This is valid only if A is a [[proper subset]] of B and/or B is a proper subset of C. However, this argument reaches a faulty conclusion if A, B, and C are [[equivalence relation|equivalent]].<ref>{{cite book |title=The use of words in reasoning |author=Alfred Sidgwick |year=1901 |publisher=A. & C. Black |url=https://archive.org/details/useofwordsinreas00sidgiala |pages=[https://archive.org/details/useofwordsinreas00sidgiala/page/297 297]–300}}</ref><ref>{{cite web |page=16 |title=Equivalence of syllogisms |author=Fred Richman |date=July 26, 2003 |publisher=Florida Atlantic University |url=http://www.math.fau.edu/richman/docs/syllog-4.pdf |url-status=dead |archive-url=https://web.archive.org/web/20100619151753/http://math.fau.edu/Richman/Docs/syllog-4.pdf |archive-date=June 19, 2010 }}</ref> In the case that A&nbsp;=&nbsp;B&nbsp;=&nbsp;C, the conclusion of the following simple aaa-1 syllogism would contradict the aao-4 argument above:


:All B is A.
:All B is A.

Latest revision as of 15:00, 23 August 2023

Negative conclusion from affirmative premises is a syllogistic fallacy committed when a categorical syllogism has a negative conclusion yet both premises are affirmative. The inability of affirmative premises to reach a negative conclusion is usually cited as one of the basic rules of constructing a valid categorical syllogism.

Statements in syllogisms can be identified as the following forms:

  • a: All A is B. (affirmative)
  • e: No A is B. (negative)
  • i: Some A is B. (affirmative)
  • o: Some A is not B. (negative)

The rule states that a syllogism in which both premises are of form a or i (affirmative) cannot reach a conclusion of form e or o (negative). Exactly one of the premises must be negative to construct a valid syllogism with a negative conclusion. (A syllogism with two negative premises commits the related fallacy of exclusive premises.)

Example (invalid aae form):

Premise: All colonels are officers.
Premise: All officers are soldiers.
Conclusion: Therefore, no colonels are soldiers.

The aao-4 form is perhaps more subtle as it follows many of the rules governing valid syllogisms, except it reaches a negative conclusion from affirmative premises.

Invalid aao-4 form:

All A is B.
All B is C.
Therefore, some C is not A.

This is valid only if A is a proper subset of B and/or B is a proper subset of C. However, this argument reaches a faulty conclusion if A, B, and C are equivalent.[1][2] In the case that A = B = C, the conclusion of the following simple aaa-1 syllogism would contradict the aao-4 argument above:

All B is A.
All C is B.
Therefore, all C is A.

See also[edit]

References[edit]

  1. ^ Alfred Sidgwick (1901). The use of words in reasoning. A. & C. Black. pp. 297–300.
  2. ^ Fred Richman (July 26, 2003). "Equivalence of syllogisms" (PDF). Florida Atlantic University. p. 16. Archived from the original (PDF) on June 19, 2010.

External links[edit]